Практикум по программированию. Основы. Ветвление. Корни уравнения
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(Difference between revisions)
Line 64: | Line 64: | ||
<pre> | <pre> | ||
+ | // g++ 4.2 | ||
+ | |||
+ | #include <iostream> | ||
+ | #include <math.h> | ||
+ | |||
+ | using namespace std; | ||
+ | |||
+ | int main() { | ||
+ | |||
+ | double a, b, c; | ||
+ | |||
+ | cout << "\n Поиск корней уравнения A * X^2 + B * X + C = 0\n"; | ||
+ | cout << "------------------------------------------------\n"; | ||
+ | |||
+ | cout << " Введите A: "; | ||
+ | cin >> a; | ||
+ | |||
+ | cout << " Введите B: "; | ||
+ | cin >> b; | ||
+ | |||
+ | cout << " Введите C: "; | ||
+ | cin >> c; | ||
+ | |||
+ | cout << "------------------------------------------------\n"; | ||
+ | |||
+ | double d = b * b - 4 * a * c; | ||
+ | double x1, x2; | ||
+ | |||
+ | if (d > 0) { | ||
+ | |||
+ | x1 = (-b + sqrt(d)) / (2 * a); | ||
+ | x2 = (-b - sqrt(d)) / (2 * a); | ||
+ | |||
+ | printf(" X1 = %.3f\n", x1); | ||
+ | printf(" X2 = %.3f\n", x2); | ||
+ | |||
+ | } else { | ||
+ | if (d == 0) { | ||
+ | |||
+ | x1 = -b / (2 * a); | ||
+ | |||
+ | printf(" X = %.3f\n", x1); | ||
+ | |||
+ | } else { | ||
+ | |||
+ | cout << " Уравнение корней не имеет\n"; | ||
+ | |||
+ | } | ||
+ | } | ||
+ | |||
+ | cout << "\n"; | ||
+ | return 0; | ||
+ | } | ||
</pre> | </pre> | ||
Revision as of 10:21, 12 April 2015
Contents |
Java
import java.util.Scanner; import java.lang.Math; public class Task01 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(); System.out.println(" Поиск корней уравнения A * X^2 + B * X + C = 0 "); System.out.println("------------------------------------------------"); System.out.print(" Введите A: "); double a = in.nextDouble(); System.out.print(" Введите B: "); double b = in.nextDouble(); System.out.print(" Введите C: "); double c = in.nextDouble(); System.out.println("------------------------------------------------"); double d = b * b - 4 * a * c; double x1, x2; if (d > 0) { x1 = (-b + Math.sqrt(d)) / (2 * a); x2 = (-b - Math.sqrt(d)) / (2 * a); System.out.printf(" X1 = %.3f\n", x1); System.out.printf(" X2 = %.3f\n", x2); } else { if (d == 0) { x1 = -b / (2 * a); System.out.printf(" X = %.3f\n", x1); } else { System.out.println(" Уравнение корней не имеет"); } } } }
C++
// g++ 4.2 #include <iostream> #include <math.h> using namespace std; int main() { double a, b, c; cout << "\n Поиск корней уравнения A * X^2 + B * X + C = 0\n"; cout << "------------------------------------------------\n"; cout << " Введите A: "; cin >> a; cout << " Введите B: "; cin >> b; cout << " Введите C: "; cin >> c; cout << "------------------------------------------------\n"; double d = b * b - 4 * a * c; double x1, x2; if (d > 0) { x1 = (-b + sqrt(d)) / (2 * a); x2 = (-b - sqrt(d)) / (2 * a); printf(" X1 = %.3f\n", x1); printf(" X2 = %.3f\n", x2); } else { if (d == 0) { x1 = -b / (2 * a); printf(" X = %.3f\n", x1); } else { cout << " Уравнение корней не имеет\n"; } } cout << "\n"; return 0; }
Pascal