Практикум по программированию. Основы. Ветвление. Корни уравнения
From AsIsWiki
(Difference between revisions)
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==Java== | ==Java== | ||
− | < | + | <source lang="java"> |
import java.util.Scanner; | import java.util.Scanner; | ||
import java.lang.Math; | import java.lang.Math; | ||
Line 14: | Line 14: | ||
public static void main(String[] args) { | public static void main(String[] args) { | ||
− | + | ||
Scanner in = new Scanner(System.in); | Scanner in = new Scanner(System.in); | ||
− | + | ||
− | + | System.out.println(); | |
System.out.println(" Поиск корней уравнения A * X^2 + B * X + C = 0 "); | System.out.println(" Поиск корней уравнения A * X^2 + B * X + C = 0 "); | ||
System.out.println("------------------------------------------------"); | System.out.println("------------------------------------------------"); | ||
− | System.out.print(" Введите A: "); | + | System.out.print(" Введите A: "); |
− | + | double a = in.nextDouble(); | |
− | System.out.print(" Введите B: "); | + | System.out.print(" Введите B: "); |
− | + | double b = in.nextDouble(); | |
− | System.out.print(" Введите C: "); | + | System.out.print(" Введите C: "); |
− | + | double c = in.nextDouble(); | |
System.out.println("------------------------------------------------"); | System.out.println("------------------------------------------------"); | ||
− | |||
− | |||
− | |||
− | + | double d = b * b - 4 * a * c; | |
+ | double x1, x2; | ||
− | + | if (d > 0) { | |
− | + | ||
− | + | x1 = (-b + Math.sqrt(d)) / (2 * a); | |
− | + | x2 = (-b - Math.sqrt(d)) / (2 * a); | |
− | + | System.out.printf(" X1 = %.3f\n", x1); | |
− | + | System.out.printf(" X2 = %.3f\n", x2); | |
− | + | } else if (d == 0) { | |
− | + | x1 = -b / (2 * a); | |
− | + | System.out.printf(" X = %.3f\n", x1); | |
− | + | } else { | |
− | + | System.out.println(" Уравнение корней не имеет"); | |
− | + | ||
+ | } | ||
} | } | ||
} | } | ||
− | </ | + | </source> |
==C++== | ==C++== | ||
− | < | + | <source lang="cpp"> |
// g++ 4.2 | // g++ 4.2 | ||
Line 100: | Line 98: | ||
printf(" X2 = %.3f\n", x2); | printf(" X2 = %.3f\n", x2); | ||
− | } else | + | } else if (d == 0) { |
− | + | ||
− | + | x1 = -b / (2 * a); | |
− | + | printf(" X = %.3f\n", x1); | |
− | + | } else { | |
− | + | cout << " Уравнение корней не имеет\n"; | |
− | |||
} | } | ||
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return 0; | return 0; | ||
} | } | ||
− | </ | + | </source> |
==Pascal== | ==Pascal== | ||
− | < | + | <source lang="delphi"> |
− | </ | + | </source> |
Revision as of 14:16, 12 March 2016
Contents |
Java
import java.util.Scanner; import java.lang.Math; public class Task01 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(); System.out.println(" Поиск корней уравнения A * X^2 + B * X + C = 0 "); System.out.println("------------------------------------------------"); System.out.print(" Введите A: "); double a = in.nextDouble(); System.out.print(" Введите B: "); double b = in.nextDouble(); System.out.print(" Введите C: "); double c = in.nextDouble(); System.out.println("------------------------------------------------"); double d = b * b - 4 * a * c; double x1, x2; if (d > 0) { x1 = (-b + Math.sqrt(d)) / (2 * a); x2 = (-b - Math.sqrt(d)) / (2 * a); System.out.printf(" X1 = %.3f\n", x1); System.out.printf(" X2 = %.3f\n", x2); } else if (d == 0) { x1 = -b / (2 * a); System.out.printf(" X = %.3f\n", x1); } else { System.out.println(" Уравнение корней не имеет"); } } }
C++
// g++ 4.2 #include <iostream> #include <math.h> using namespace std; int main() { double a, b, c; cout << "\n Поиск корней уравнения A * X^2 + B * X + C = 0\n"; cout << "------------------------------------------------\n"; cout << " Введите A: "; cin >> a; cout << " Введите B: "; cin >> b; cout << " Введите C: "; cin >> c; cout << "------------------------------------------------\n"; double d = b * b - 4 * a * c; double x1, x2; if (d > 0) { x1 = (-b + sqrt(d)) / (2 * a); x2 = (-b - sqrt(d)) / (2 * a); printf(" X1 = %.3f\n", x1); printf(" X2 = %.3f\n", x2); } else if (d == 0) { x1 = -b / (2 * a); printf(" X = %.3f\n", x1); } else { cout << " Уравнение корней не имеет\n"; } cout << "\n"; return 0; }
Pascal