Практикум по программированию. Основы. Циклы. Простые числа
From AsIsWiki
(Difference between revisions)
Line 14: | Line 14: | ||
public static void main(String[] args) { | public static void main(String[] args) { | ||
− | + | ||
Scanner in = new Scanner(System.in); | Scanner in = new Scanner(System.in); | ||
− | + | ||
− | + | System.out.println(); | |
− | System.out.println(" Поиск простых чисел "); | + | System.out.println(" Поиск простых чисел"); |
System.out.println("---------------------"); | System.out.println("---------------------"); | ||
− | System.out.print(" Введите число: "); | + | System.out.print(" Введите число: "); |
− | + | long n = in.nextLong(); | |
− | + | long i = 2; | |
− | + | while ((i <= n / 2) && (n % i != 0)) { | |
− | + | i++; | |
− | + | } | |
− | + | String no = i <= n / 2 ? "не " : ""; | |
− | + | ||
− | + | ||
− | + | System.out.println("---------------------"); | |
− | + | System.out.printf(" Число %d - %sпростое\n", n, no); | |
− | + | ||
− | + | ||
− | + | ||
} | } | ||
} | } | ||
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cout << " Введите число: "; | cout << " Введите число: "; | ||
cin >> n; | cin >> n; | ||
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long i = 2; | long i = 2; | ||
Line 73: | Line 64: | ||
} | } | ||
− | + | string no = i <= n / 2 ? "не " : ""; | |
− | + | ||
− | + | ||
− | cout << " | + | cout << "---------------------\n"; |
+ | printf(" Число %ld - %sпростое\n\n", n, no.data()); | ||
return 0; | return 0; |
Revision as of 13:39, 21 March 2016
Contents |
Java
import java.util.Scanner; public class Task06 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(); System.out.println(" Поиск простых чисел"); System.out.println("---------------------"); System.out.print(" Введите число: "); long n = in.nextLong(); long i = 2; while ((i <= n / 2) && (n % i != 0)) { i++; } String no = i <= n / 2 ? "не " : ""; System.out.println("---------------------"); System.out.printf(" Число %d - %sпростое\n", n, no); } }
C++
// g++ 4.2 #include <iostream> using namespace std; int main() { long n; cout << "\n Поиск простых чисел\n"; cout << "---------------------\n"; cout << " Введите число: "; cin >> n; long i = 2; while ((i <= n / 2) && (n % i != 0)) { i++; } string no = i <= n / 2 ? "не " : ""; cout << "---------------------\n"; printf(" Число %ld - %sпростое\n\n", n, no.data()); return 0; }
Pascal
JavaScript