Практикум по программированию. Основы. Циклы. Сумма квадратов чисел
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(Difference between revisions)
Line 13: | Line 13: | ||
public static void main(String[] args) { | public static void main(String[] args) { | ||
− | + | ||
Scanner in = new Scanner(System.in); | Scanner in = new Scanner(System.in); | ||
− | + | ||
− | + | System.out.println(); | |
− | System.out.println(" Сумма квадратов чисел от 1 до N "); | + | System.out.println(" Сумма квадратов чисел от 1 до N"); |
System.out.println("---------------------------------"); | System.out.println("---------------------------------"); | ||
− | System.out.print(" Введите N: "); | + | System.out.print(" Введите N: "); |
− | + | long n = in.nextLong(); | |
− | + | ||
− | + | ||
− | + | long s = 0; | |
− | + | for (long i = 1; i <= n; i++) { | |
− | + | s += i * i; | |
− | + | } | |
− | + | System.out.println("---------------------------------"); | |
+ | System.out.printf(" S = %d\n", s); | ||
} | } | ||
} | } | ||
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cout << " Введите N: "; | cout << " Введите N: "; | ||
cin >> n; | cin >> n; | ||
− | |||
− | |||
long s = 0; | long s = 0; | ||
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s += i * i; | s += i * i; | ||
} | } | ||
− | + | ||
+ | cout << "---------------------------------\n"; | ||
printf(" S = %ld\n\n", s); | printf(" S = %ld\n\n", s); | ||
Revision as of 11:38, 21 March 2016
Contents |
Java
import java.util.Scanner; public class Task01 { public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.println(); System.out.println(" Сумма квадратов чисел от 1 до N"); System.out.println("---------------------------------"); System.out.print(" Введите N: "); long n = in.nextLong(); long s = 0; for (long i = 1; i <= n; i++) { s += i * i; } System.out.println("---------------------------------"); System.out.printf(" S = %d\n", s); } }
C++
// g++ 4.2 #include <iostream> using namespace std; int main() { long n; cout << "\n Сумма квадратов чисел от 1 до N\n"; cout << "---------------------------------\n"; cout << " Введите N: "; cin >> n; long s = 0; for (long i = 1; i <= n; i++) { s += i * i; } cout << "---------------------------------\n"; printf(" S = %ld\n\n", s); return 0; }
Pascal
JavaScript